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Timeline for Nonlinear boolean functions

Current License: CC BY-SA 4.0

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Nov 5, 2018 at 16:01 vote accept Michele
Nov 5, 2018 at 14:32 answer added Jyrki Lahtonen timeline score: 1
Nov 5, 2018 at 13:55 comment added Michele @JyrkiLahtonen. Yees... This seems to work, and is way simpler than the GRS construction pointed to by Kodlu (whom I thank, anyway). Can you write this as an answer? Also if you have any suggestion on ways to make it more efficient, I would greatly appreciate it.
Nov 3, 2018 at 10:53 history edited Michele CC BY-SA 4.0
Question edited so as to avoid trivial answers based on taking an exponential large $m$. Also I have made clear that I am interested in an algorithm/construction to (effectively) build $f$. Same question posted on cryptostackexchange <https://crypto.stackexchange.com/questions/63665/finding-nonline>
Nov 2, 2018 at 22:14 answer added kodlu timeline score: 1
Nov 2, 2018 at 21:57 comment added Michele I do not fix n-1 members, as I require that the property holds for each set $S$ (I changed for any to for each to make this more explicit).
Nov 2, 2018 at 21:56 history edited Michele CC BY-SA 4.0
added 1 character in body
Nov 2, 2018 at 21:34 comment added Gerhard Paseman Indeed, if you fix n-1 members of the set, you have fewer than 2^{m-n+1} choices for the remaining assignment. Gerhard "Wonders About Shape Of Image" Paseman, 2018.11.02.
Nov 2, 2018 at 19:56 comment added Michele @Mikhail. The structure of $F_2^n$ might come into play when spelling out the conditions on $f$ and $m$ (e.g. $m-n$ might be required to be large enough etc.).
Nov 2, 2018 at 19:35 comment added Mikhail Tikhomirov The structure of $\mathbf{F}_2^n$ is not important, is it? As it is written now, we could talk about a subset of $\mathbf{F}_2^m$ or size $2^n$ instead of $\mathrm{Im} f$ just the same.
Nov 2, 2018 at 19:22 history asked Michele CC BY-SA 4.0