Timeline for For which $n$, can we find a sequence of $n+1$ distinct points s.t. the interpolating polynomial of every +ve continuous function is itself +ve
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Oct 27, 2018 at 22:37 | vote | accept | user521337 | ||
| Oct 27, 2018 at 17:42 | history | edited | Gerald Edgar | CC BY-SA 4.0 |
added 211 characters in body
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| Oct 27, 2018 at 17:37 | history | edited | Gerald Edgar | CC BY-SA 4.0 |
added 211 characters in body
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| Oct 27, 2018 at 17:34 | comment | added | Gerald Edgar | OK, $n+1$ nodes means the approximation has degree $n$ Fixing. | |
| Oct 27, 2018 at 16:23 | comment | added | user521337 | For $n=2$, you need nodes $x_0,x_1,x_2$ ... also, is your $f(x)$ positive only at the nodes ? If it so, then you've got it wrong, I want $f:[a,b]\to (0,\infty)$, that means $f(x)>0,\forall x\in [a,b]$ | |
| Oct 27, 2018 at 0:49 | comment | added | user521337 | and for $n=2$ ... ? | |
| Oct 26, 2018 at 19:16 | history | edited | Gerald Edgar | CC BY-SA 4.0 |
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| Oct 26, 2018 at 19:11 | history | answered | Gerald Edgar | CC BY-SA 4.0 |