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Oct 26, 2018 at 15:23 comment added user44143 Miller’s result is constructive, though the procedure is more complicated than is needed here. In his notation: Let $f$ be a superpolynomial function, $h’ \sim f’/f$, $g = h \circ f^{-1}$, $G(t)=\lim_{x\rightarrow \infty}(g(xt)-g(x))$; then $\log t=G(t)/G’(1)$, $\exp=\log^{-1}$.
Oct 26, 2018 at 14:42 vote accept Andreas Thom
Oct 26, 2018 at 13:08 answer added user44143 timeline score: 10
Oct 26, 2018 at 12:54 history edited Andreas Thom CC BY-SA 4.0
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Oct 26, 2018 at 12:19 history asked Andreas Thom CC BY-SA 4.0