Timeline for Orthogonal basis of polynomials?
Current License: CC BY-SA 4.0
8 events
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Sep 13, 2021 at 15:33 | comment | added | Hexhist | The 3 term recurrence relation does not immediately imply that the $p_n$ do not have a common root. In fact, if $p_n$ and $p_{n-1}$ have the same root, the recursion implies that $p_{n+1}$ has also the same root. The reason that common roots are not allowed is more subtle. In any event, I do consider that Fernando’s question is a very interesting one, and deserves a more informative answer, if possible. | |
Oct 25, 2018 at 23:28 | comment | added | Chris Godsil | Any text book on orthogonal polynomials should treat this, it’s quite basic. My “Algebraic Combinatorics” discusses it at lengh too ( if you’ll forgive the plug). | |
Oct 25, 2018 at 23:04 | comment | added | user41593 | Very nice answer! Do you know of a reference elaborating on this link between orthogonality and recurrences? | |
Oct 25, 2018 at 22:38 | vote | accept | fernando | ||
Oct 25, 2018 at 22:38 | vote | accept | fernando | ||
Oct 25, 2018 at 22:38 | |||||
Oct 25, 2018 at 22:35 | comment | added | fernando | Thank you very much! Indeed you are right. But can we define something similar to a orthogonality condition? e.g. we can also consider the family of polynomials P_n(x) = x^n, which is a complete basis, but in this case we can define, for instance $<P_n P_m> = \int \frac{dz}{z} P_n(x) P_{-m}(x)$, where the integral is a contour integral around zero. | |
Oct 25, 2018 at 22:34 | vote | accept | fernando | ||
Oct 25, 2018 at 22:38 | |||||
Oct 25, 2018 at 22:29 | history | answered | Chris Godsil | CC BY-SA 4.0 |