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Oct 24, 2018 at 18:58 history edited Uriya First CC BY-SA 4.0
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Oct 24, 2018 at 18:47 comment added Benjamin Steinberg thanks! That is what I was looking for. I
Oct 24, 2018 at 18:46 vote accept Benjamin Steinberg
Oct 24, 2018 at 18:23 comment added Uriya First @BenjaminSteinberg The difference is indeed superfluous. I added an answer to your question about whether the dimension is countable (it is).
Oct 24, 2018 at 18:19 history edited Uriya First CC BY-SA 4.0
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Oct 24, 2018 at 18:00 comment added Benjamin Steinberg by the way I think the slight difference is superfluous since localization is exact and so localizing $(K/P)$ at $P$ amounts to first localizing $K$ at $P$ and $P$ at $P$ and then moding out, but localizing $K$ at $P$ does nothing.
Oct 24, 2018 at 17:25 comment added Benjamin Steinberg My real interest is in the dimension over $\mathbb C$. Maybe some parentheses on the localization might help. I have plus one but I really would like to see a prufer group like description in this particular case preferably with a basis over $\mathbb C$. I will add that to the question to be clear.
Oct 24, 2018 at 17:18 comment added Uriya First @Benjamin You are correct in your understanding, with the slight difference that only the $R$-module$P$ is localized at the prime ideal $P$. (Localizing $K$ at $P$ gives back $K$.) I agree that this is not as explicit as in the case $R=\mathbb{Z}$ mentioned in the comments. I will think more about it.
Oct 24, 2018 at 17:06 comment added Benjamin Steinberg I’m having trouble parsing this. Do I view K,P as R-modules, take the quotient $K/P$ as an R-module and then localize at P? Is it easy to see what this amounts to concretely? In my original example what I really want to know is whether the injective indecomposables can have countable dimension over $\mathbb C$ so I was hoping for something more explicit.
Oct 24, 2018 at 16:20 history answered Uriya First CC BY-SA 4.0