Timeline for Spin cobordism v.s. KO theory in low or in any dimensions
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Nov 20, 2018 at 0:36 | comment | added | wonderich | I asked one more related question for the Pin cases --- please feel free to answer/comments - thanks - I am not sure what will be the related K theory. | |
| Nov 20, 2018 at 0:25 | vote | accept | wonderich | ||
| Nov 20, 2018 at 0:24 | comment | added | wonderich | Thanks for the answer/comments - I hope it is correct. +1 | |
| Oct 24, 2018 at 8:01 | history | edited | user43326 | CC BY-SA 4.0 |
Corrected factual errors.
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| Oct 23, 2018 at 8:31 | comment | added | user43326 | @ArunDebray You are right, $n(J)$ even, so we get $\Sigma ^8ko$. With $n(J)$ odd sequences, we are not allowed to have 1 so the lowest is $\Sigma 8ko<2>$. Presumably in the range the op asks, there is no HZ/2 summand, I will correct my answer later, thanks. | |
| Oct 22, 2018 at 16:51 | comment | added | Arun Debray | Are you sure it's a $\Sigma^4\mathit{ko}$, and not a $\Sigma^8\mathit{ko}$? $\pi_5\mathit{MSpin}$ and $\pi_6\mathit{MSpin}$ both vanish, but if $\mathit{MSpin}$ had a $\Sigma^4\mathit{ko}$ summand, they would both contain a $\mathbb Z/2$ summand. | |
| Oct 22, 2018 at 16:44 | history | answered | user43326 | CC BY-SA 4.0 |