Timeline for Unboundedness of the Sobolev norm of a sequence : Does it follow from Sobolev embedding?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 23, 2018 at 1:50 | vote | accept | Rajesh D | ||
| Oct 21, 2018 at 14:49 | answer | added | Nate Eldredge | timeline score: 2 | |
| Oct 21, 2018 at 13:58 | answer | added | Rajesh D | timeline score: 1 | |
| Oct 21, 2018 at 12:49 | comment | added | Rajesh D | @Hannes : looks like you have missed the key word "pointwise" in my question. There are two types of convegwnce i am talking about in this question. One pointwise and other in the norm and i have mentioned them appropriately. | |
| Oct 21, 2018 at 11:58 | comment | added | Hannes | Watch out: The way you construct $f$ from $g$ implies that $f$ and $g$ represent the same equivalence class in $H^k(\mathbb{R}^m)$. So the fact that $f$ is discontinuous does not imply anything about $(f_n) \not\to f$ in $H^k(\mathbb{R}^m)$ here. Otherwise your statement $f \in H^k(\mathbb{R}^m)$ would also be bogus. | |
| Oct 21, 2018 at 8:58 | history | asked | Rajesh D | CC BY-SA 4.0 |