Timeline for How does multiplication affect degrees?
Current License: CC BY-SA 4.0
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| when toggle format | what | by | license | comment | |
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| Oct 20, 2018 at 10:55 | comment | added | Jason Starr | I tried to find counterexamples with solvable subgroups. But then I realized that for a solvable subgroup $B$, the product $B\cdot B$ equals $B$ since it is a subgroup. So the identity is true for $B=B$ a subgroup. Then I tried the simplest one-dimensional subvarieties of the Borel that were actually distinct. | |
| Oct 20, 2018 at 10:50 | history | answered | H A Helfgott | CC BY-SA 4.0 |