Timeline for Equivalence of surjections from a surface group to a free group
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Oct 18, 2018 at 2:28 | comment | added | user101010 | @JeanRaimbault Thanks this is perfect. I am trying to do this algorithmically also - is it clear how lemma 2.2 can be made effective? I.e. given the surface with the labeled generators and a surjection to a free group, how do we find the set of curves to attach to the surface to realize the handlebody that realizes the surjection? | |
| Oct 18, 2018 at 2:05 | vote | accept | user101010 | ||
| Oct 15, 2018 at 16:45 | comment | added | Jean Raimbault | I would say no, because it seems unlikely to me that any automorphism of the free group induces an homeomorphism of the handlebody, and barring that I have no idea about your lifting problem and I see no indication about it in Leininger--Reid's arguments (but I'm not a specialist so I might be missing something obvious). | |
| Oct 15, 2018 at 8:17 | comment | added | YCor | Do you know if the set of surjective homomorphisms onto $F_g$ is a singleton modulo $Aut(\pi_1(S))$ (instead of modding out by $Aut(\pi_1(S))\times Aut(F_g)$)? this is related to the question whether automorphisms of $F_k$ can be lifted to automorphisms of $\pi_1(S)$. | |
| Oct 15, 2018 at 5:42 | history | answered | Jean Raimbault | CC BY-SA 4.0 |