Timeline for Is there another quantum deformation of sl(2)?
Current License: CC BY-SA 4.0
13 events
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| Apr 27, 2019 at 1:29 | history | edited | Konstantinos Kanakoglou |
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| Oct 24, 2018 at 6:48 | vote | accept | Jedy | ||
| Oct 22, 2018 at 22:52 | history | edited | Konstantinos Kanakoglou |
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| Oct 22, 2018 at 18:56 | history | edited | Konstantinos Kanakoglou |
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| Oct 22, 2018 at 16:41 | answer | added | Konstantinos Kanakoglou | timeline score: 4 | |
| Oct 17, 2018 at 2:07 | comment | added | Jedy | To Victor, You are right, but multiplicative commutation relations with $E$ and $F$ are nothing else than rewrting of two of three defining relations. How are you going to add second parameter of deformation $p$? Could you please write it here? | |
| Oct 17, 2018 at 1:59 | comment | added | Jedy | To Alex, Under $Fun(D)$ was meant any arbitary function of generator $D$. It is easy to check that Jacobi identity is satisfied as well. (I do realize that it is not enough for algebra to be quantum) | |
| Oct 14, 2018 at 23:54 | comment | added | Victor Protsak | Perhaps I am missing something, but if you are including Lie element $H$ in the generators along with group-like $q^{\pm H}$ (for which you would also need to specify the multiplicative commutation relations with $E$ and $F$), you are getting not the "standard" deformation, but rather a certain extension. Having said that, there are 2- parameter "quantum groups", where the relations involve $p$ and $q$. | |
| Oct 14, 2018 at 13:20 | comment | added | Alex M. | What exactly is $Fun(D)$? | |
| S Oct 14, 2018 at 13:18 | history | suggested | Mee Seong Im | CC BY-SA 4.0 |
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| Oct 14, 2018 at 12:21 | review | Suggested edits | |||
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| Oct 14, 2018 at 11:00 | review | First posts | |||
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| Oct 14, 2018 at 10:58 | history | asked | Jedy | CC BY-SA 4.0 |