Timeline for Does a projective variety have only finitely many associated Hilbert polynomials?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Oct 13, 2018 at 16:00 | vote | accept | Paolo Avi | ||
| Oct 13, 2018 at 15:55 | comment | added | R. van Dobben de Bruyn | Yes, that is the conclusion. (It's universal in a weak sense, because it depends on some choices.) I also worked out one non-trivial example, to show that it's not so easy to get a complete parametrisation of all Hilbert polynomials obtained this way. | |
| Oct 13, 2018 at 15:54 | comment | added | Paolo Avi | @R.vanDobbendeBruyn Do I understand correctly that your answer says that, given a choice of generators, one obtains a "universal" polynomial $p$ (in the sense that any other Hilbert polynomial is a very specific type of specialization of this one)? | |
| Oct 13, 2018 at 15:29 | comment | added | R. van Dobben de Bruyn | As Sasha rightly points out, the answer to the second question is negative because you can take linear combinations of line bundles. My answer to this question contains a slightly modified statement you can deduce from finite generation of the Néron–Severi group. | |
| Oct 13, 2018 at 15:12 | answer | added | Sasha | timeline score: 7 | |
| Oct 13, 2018 at 15:05 | review | First posts | |||
| Oct 13, 2018 at 15:55 | |||||
| Oct 13, 2018 at 15:04 | history | asked | Paolo Avi | CC BY-SA 4.0 |