Timeline for Lattice points in a square pairwise-separated by integer distances
Current License: CC BY-SA 4.0
16 events
| when toggle format | what | by | license | comment | |
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| Nov 20, 2018 at 10:18 | answer | added | Ilya Bogdanov | timeline score: 3 | |
| Oct 14, 2018 at 0:26 | history | edited | Joseph O'Rourke | CC BY-SA 4.0 |
added 2 characters in body
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| Oct 14, 2018 at 0:18 | answer | added | Joseph O'Rourke | timeline score: 2 | |
| Oct 14, 2018 at 0:11 | comment | added | Anthony Quas | There should be 16 1’s... (starting at 10 and ending at 25). | |
| Oct 13, 2018 at 22:36 | answer | added | Fedor Petrov | timeline score: 6 | |
| Oct 13, 2018 at 21:18 | answer | added | Igor Rivin | timeline score: 5 | |
| Oct 13, 2018 at 19:08 | history | edited | Joseph O'Rourke | CC BY-SA 4.0 |
added 283 characters in body
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| Oct 13, 2018 at 14:24 | comment | added | Joseph O'Rourke | @GerryMyerson: Thanks for that reference. I wonder if there is a difference between not-all-collinear and general position (no three in a line, no four on a circle)? | |
| Oct 13, 2018 at 5:28 | comment | added | Anthony Quas | If $d=25$, then in $S(2)$, the four points: the origin: $e_1+....+e_9$, $e_{10}+....+e_{25}$ and $e_1+....+e_{25}$ are each separated by integer distances | |
| Oct 13, 2018 at 3:12 | comment | added | Gerry Myerson | The Kreisel & Kurz paper is available at wm-archive.uni-bayreuth.de/fileadmin/Sascha/Publikationen2/… | |
| Oct 13, 2018 at 3:01 | comment | added | Gerry Myerson | I believe the current record for points in the plane, no three in a line, no four on a circle, all distances integral, is seven, as in Tobias Kreisel and Sascha Kurz, There are integral heptagons, no three points on a line, no four on a circle, Discrete Comput. Geom. 39 (2008), no. 4, 786–790, MR2413160 (2009d:52021) | |
| Oct 13, 2018 at 1:08 | history | edited | Joseph O'Rourke | CC BY-SA 4.0 |
Resized fig.
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| Oct 13, 2018 at 1:01 | comment | added | Joseph O'Rourke | @AnthonyQuas: Thanks! Revised rational$\rightarrow$integer. | |
| Oct 13, 2018 at 1:00 | history | edited | Joseph O'Rourke | CC BY-SA 4.0 |
Anthony's point.
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| Oct 13, 2018 at 0:17 | comment | added | Anthony Quas | Note that $\sqrt{x\cdot x}$ is rational if and only if it’s integral, so you may as well ask for integer distances. | |
| Oct 13, 2018 at 0:08 | history | asked | Joseph O'Rourke | CC BY-SA 4.0 |