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Oct 10, 2018 at 11:41 comment added Francois Ziegler It is consistent. The formula (Barut–Rączka p. 553) assumes positive helicity, includes $M=0$ in the integral, and says nothing about multiplicity. For more details see the quoted papers.
Oct 10, 2018 at 11:20 comment added Arnold Neumaier @FrancoisZiegler: But massless cases have positive and negative helicity for each J, and even ignoring that, the formula you gave is not consistent with that in Lomont's paper - there is an extra contribution of massless representations with inifinite multiplicity.
Oct 10, 2018 at 10:52 comment added Francois Ziegler @Arnold No, massive would be $U^{M_1,\,J_1}\otimes U^{M_2,\,J_2}$.
Oct 10, 2018 at 10:50 comment added Arnold Neumaier @FrancoisZiegler: But this is the massive case, whereas I had asked for the massless case.
Oct 10, 2018 at 10:37 comment added Francois Ziegler +1. Also Moussa–Stora (1965), Schaaf (1970), Barut–Rączka (1977, p. 553): $$U^{0,\,J_1}\otimes U^{0,\,J_2}\cong\int_0^\infty dM\sum_{J=|J_1-J_2|}^{\infty} \oplus U^{M,\,J}.$$
Oct 10, 2018 at 10:21 vote accept Arnold Neumaier
Oct 10, 2018 at 10:20 comment added Arnold Neumaier Thanks! There is a second paper by Lomont and Moses that gives a more explicit reduction: Reduction of Reducible Representations of the Infinitesimal Generators of the Proper, Orthochronous, Inhomogeneous Lorentz Group,aip.scitation.org/doi/pdf/10.1063/1.1705287
Oct 10, 2018 at 9:12 history answered Zurab Silagadze CC BY-SA 4.0