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Oct 26, 2018 at 0:12 vote accept André Porto
Oct 26, 2018 at 0:11 vote accept André Porto
Oct 26, 2018 at 0:12
Oct 21, 2018 at 1:44 answer added André Porto timeline score: 0
Oct 21, 2018 at 1:41 history edited André Porto CC BY-SA 4.0
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Oct 20, 2018 at 15:50 answer added Dirk Werner timeline score: 2
Oct 5, 2018 at 5:08 vote accept André Porto
Oct 26, 2018 at 0:11
Oct 5, 2018 at 5:04 history edited André Porto CC BY-SA 4.0
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Oct 5, 2018 at 4:35 answer added Nate Eldredge timeline score: 8
Oct 5, 2018 at 4:22 comment added Nate Eldredge Okay, it just sounded weird to talk about the variation of a positive measure.
Oct 5, 2018 at 4:21 comment added André Porto No, "measure" here means "positive measure".
Oct 5, 2018 at 4:14 comment added Nate Eldredge I guess "measure" here means "signed measure"? Is there an obvious reduction to positive measures? Anyway, I would suppose the contrary; then by regularity every point has an open neighborhood of measure $< 2/3 + \epsilon$. By compactness you can find a finite cover by such neighborhoods. It seems like one ought to be able to obtain a contradiction eventually.
Oct 5, 2018 at 3:56 history asked André Porto CC BY-SA 4.0