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Sep 29, 2018 at 14:43 vote accept Daniel López
Sep 28, 2018 at 23:22 answer added Nate Eldredge timeline score: 7
Sep 28, 2018 at 23:15 comment added Christian Chapman if you're just interested in the johnson-lindenstrauss lemma you can find a different component distribution for your matrices where it still holds, and have subgaussian tails (for instance, i think rademacher rvs work)
Sep 28, 2018 at 23:06 comment added Christian Chapman did you know it is a difference of iid chi-squared distributions with one dof? this makes me guess that it is not sub-gaussian, as the tail of one of them is shaped like $\exp(-x/2-\ln(x)/2)$ which is eventually greater than anything like $e^{-ax^2}, a>0$
Sep 28, 2018 at 22:30 review First posts
Sep 28, 2018 at 23:15
Sep 28, 2018 at 22:27 history asked Daniel López CC BY-SA 4.0