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Sep 29, 2018 at 7:47 comment added Nick L One may check that the map $c$ maps $D$ to $c_{1}(\mathcal{O}(D))$. If D is effective then there will be a section $s \in H^{0}(\mathcal{O}(D))$ whose zero-set is $D$. Then by definition of the first Chern class, this will be the Poincare dual of $D$. Now we can extend by linearity.
Sep 29, 2018 at 0:12 comment added Vincenzo Zaccaro The main issue is just proving that, for a prime divisor, the element $c(D)$ is the Poincarè dual of $D$.
Sep 28, 2018 at 8:58 history edited Nick L CC BY-SA 4.0
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Sep 28, 2018 at 8:46 history answered Nick L CC BY-SA 4.0