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Timeline for Pull-back divisor being Cartier

Current License: CC BY-SA 4.0

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Sep 27, 2018 at 1:14 vote accept Joaquín Moraga
Sep 26, 2018 at 22:59 comment added Hacon What if $Y$ is a smooth curve and $\pi $ is a stable family that has a double fiber over $y\in Y$. Then isn't $\pi ^*((1/2)y)$ Cartier? If we assume $N$ is integral, then we have an inclusion $\pi _* O_X(\pi ^* N)\to O_Y(N)$ where the LHS is torsion free and the RHS is reflexive. This is an isomorphism over the smooth locus of $Y$ (by the projection formula). But it is also surjective since if $f\in k(Y)$ satisfies $(f)+N\geq 0$, then $f\circ \pi \in k(X)$ satisfies $(f\circ \pi)+f^*N\geq 0$ which shows the inclusion is a surjection.
Sep 26, 2018 at 22:57 answer added Jason Starr timeline score: 5
Sep 26, 2018 at 22:43 comment added Jason Starr @Stefano. You are correct. I did not read the previous comment about the definition of pullback in this context (I assumed the pullback was inverse image ideal sheaf).
Sep 26, 2018 at 22:22 comment added Stefano @JasonStarr Isn't the pullback of $N$ in this case the strict transform plus $\frac 1 2 E$, where $E$ is the exceptional curve?
Sep 26, 2018 at 22:16 comment added Jason Starr Let $Y\subset \mathbb{P}^3$ be a projective cone over a smooth plane conic, i.e., $Y$ is a quadric hypersurface of rank $3$. Let $\pi$ be the minimal desingularization. Let $N$ be one of the lines of ruling on $Y$.
Sep 26, 2018 at 22:14 comment added Joaquín Moraga $\pi^*(N):=\frac{\pi^*(mN)}{m}$, for $m$ divisible enough so that $mN$ is Cartier, where $\pi^*(nM)$ is the pull-back of Cartier divisors.
Sep 26, 2018 at 22:12 comment added David E Speyer Thanks! While we're at it, can you clarify: Does pulling back $N$ mean taking the sum of the components of $\pi^{-1}(N)$ with appropriate multiplicity, or do you mean that $\pi^{\ast} \mathcal{O}(N)$ is locally principal?
Sep 26, 2018 at 22:11 comment added Joaquín Moraga I think your counter-example does not have connected fibers.
Sep 26, 2018 at 22:10 comment added David E Speyer Duplicate of math.stackexchange.com/questions/60591/… , I think.
Sep 26, 2018 at 22:07 history asked Joaquín Moraga CC BY-SA 4.0