Timeline for Derived equivalences and the Coxeter polynomial
Current License: CC BY-SA 4.0
8 events
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
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| Sep 26, 2018 at 8:41 | comment | added | Mare | @JeremyRickard Ah right because the quiver of this radical square zero algebra is not a tree. | |
| Sep 26, 2018 at 8:02 | comment | added | Jeremy Rickard | The radical square zero example for $Q=A_3$ has finite representation type but is not derived equivalent to $KQ$. | |
| Sep 26, 2018 at 7:59 | comment | added | Mare | @JeremyRickard Thanks, maybe being representation-finite is a good condition? At least it might exclude the radical square zero example. | |
| Sep 26, 2018 at 7:58 | history | edited | Mare | CC BY-SA 4.0 |
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| Sep 26, 2018 at 7:51 | comment | added | Jeremy Rickard | You definitely need to restrict to Nakayama algebras (or at least have some extra conditions on $A$). For example, if $A$ is the radical square zero algebra with the same Cartan matrix as $KQ$, then it’s not usually derived equivalent to $KQ$: for $Q=A_n$ with all arrows in the same direction, $A$ has infinite representation type if $n>3$. | |
| Sep 25, 2018 at 21:28 | history | edited | Mare | CC BY-SA 4.0 |
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| Sep 25, 2018 at 21:07 | history | asked | Mare | CC BY-SA 4.0 |