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S May 14, 2023 at 15:19 history suggested The Amplitwist CC BY-SA 4.0
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S May 14, 2023 at 15:19
Jul 12, 2010 at 19:51 comment added domotorp I think that the 5-cycle is just a graph for which the answer is NO. As it contains no matching*, it does not have a coloring which each colorclass having size at least two.
Jul 12, 2010 at 13:01 comment added Niel de Beaudrap A 5-cycle is it's own complement, and contains neither a perfect-matching, nor a perfect-matching-asterisk. Thus, the 5-cycle is a graph for which your reduction does not work.
Jul 9, 2010 at 17:44 history edited domotorp CC BY-SA 2.5
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Jul 9, 2010 at 13:44 history edited domotorp CC BY-SA 2.5
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Jul 9, 2010 at 13:37 comment added domotorp That is why I wrote matching* and not matching - I said that we also allow K_3's to be matched together. It is unnecessary to allow bigger cliques. I don't get what you are trying to say with the 5-cycle.
Jul 9, 2010 at 13:08 comment added Niel de Beaudrap If the graph has a perfect matching, then this suffices to yield a solution; but the original problem is not equivalent to whether the complement has a perfect matching. Again, consider the 5-cycle. --- More generally, it suffices for the complement to be covered by a vertex-disjoint collection of cliques, where each clique has size at least 2; a perfect matching is a special case.
Jul 8, 2010 at 22:28 comment added Rune +1 for the statement "it is not hard to show that it is in P. Or NP-complete..."
Jul 8, 2010 at 20:42 history answered domotorp CC BY-SA 2.5