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Timeline for An analytical zero divisor

Current License: CC BY-SA 4.0

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Sep 22, 2018 at 10:36 comment added MSMalekan Thanks for the references provided in the answer. It is worth mentioning here that for $\alpha\in\text{vN}(G)$, $I:=\{\beta\in\text{vN}(G): \alpha\beta=0\}$ is a right ideal of vN$(G)$, closed in strong topology, so there is a projection $p\in\text{vN}(G)$ such that $I=p(\text{vN}(G))$.
Sep 22, 2018 at 10:29 vote accept MSMalekan
Sep 21, 2018 at 14:50 history answered Steffen Kionke CC BY-SA 4.0