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Sep 22, 2018 at 23:49 vote accept Turbo
Sep 22, 2018 at 23:48 vote accept Turbo
Sep 22, 2018 at 23:48
Sep 22, 2018 at 23:23 comment added Turbo @GjergjiZaimi This will definitely help.
Sep 22, 2018 at 23:19 comment added Gjergji Zaimi @Freeman. I expanded the answer to contain the generating functions in all cases and how they are derived. Hope this helps.
Sep 22, 2018 at 23:18 history edited Gjergji Zaimi CC BY-SA 4.0
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Sep 22, 2018 at 20:36 vote accept Turbo
Sep 22, 2018 at 20:37
Sep 22, 2018 at 20:36 vote accept Turbo
Sep 22, 2018 at 20:36
Sep 22, 2018 at 17:36 comment added Gjergji Zaimi The general technique is outlined here en.wikipedia.org/wiki/Symbolic_method_(combinatorics) A great place to learn about it is Flajolet and Sedgewick's book Analytic Combinatorics.
Sep 22, 2018 at 17:34 comment added Gjergji Zaimi @Freeman. It is a fundamental theorem in combinatorics. It roughly says that if $F(x)$ is the exponential generating function of some structures, then $e^F$ is the exponential generating function of disjoint unions of such structures. For the example above, I can find the exponential generating function of even cycles to be $F(x)=\frac{x^2}{2}+\frac{x^4}{4}+\cdots$ since there are exactly $(2n-1)!$ cycles of size $2n$. Therefore $e^{tF}$ is the exponential generating function of disjoint unions of even cycles, together with a statistic $t$ that keeps track of the number of cycles.
Sep 22, 2018 at 9:39 comment added Turbo @GjergjiZaimi What exactly is the exponential formula?
Sep 21, 2018 at 2:57 comment added T. Amdeberhan Accordingly, $f(2n+1,k)=0$ and $f(2n,k)=\frac1{n!}e_{n-k}(1,2,\dots,n-1)$ where $e_j$ is the elementary symmetric function of $1,2,\dots,n-1$.
Sep 21, 2018 at 2:38 history edited Gjergji Zaimi CC BY-SA 4.0
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Sep 21, 2018 at 2:27 history answered Gjergji Zaimi CC BY-SA 4.0