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Oct 2, 2011 at 15:31 comment added timur If $D$ is open, $C(D)$ and $C(\bar{D})$ are different. If we follow these lines, what we call the Lipschitz space would be $C^{0,1}(\bar{D})$, and $C^{0,1}(D)$ would be something like a locally Lipschitz space. But I have never seen such distinction notationally for Lipschitz spaces.
Oct 23, 2010 at 9:46 comment added Pietro Majer For a domain $D\subset \mathbb{R}^n$ I would definitely go for Willie's suggestion as the standard ones. The notations $\mathrm{Lip}(X)$ and $\mathrm{Lip}_k(X)$ are quite standard for the Lipschitz functions on the metric space $X$, resp., the k-Lipschitz functions on $X .$
Jul 10, 2010 at 20:03 comment added Kevin H. Lin \operatorname ftw!
Jul 9, 2010 at 4:19 comment added Tom LaGatta Both Yemon and Willie gave good answers. If either one wants to leave their comment as an answer to the question, I'll be happy to choose it to give them some points. Willie, since your reputation score is lower, you have first dibs.
Jul 9, 2010 at 1:08 comment added Harald Hanche-Olsen Since the question has been satisfactorily answered in the comments, I am voting to close as no longer relevant. Not because it's a bad question, but we don't want it to get regularly bumped to the front page as an unanswered question, do we?
Jul 8, 2010 at 20:34 comment added Harald Hanche-Olsen Yeah, but if you go with Yemon's notation then for goodness' sake write it as $\operatorname{Lip}_1(D)$ or $\operatorname{Lip}(D)$.
Jul 8, 2010 at 20:03 comment added Tom LaGatta Both those notations are nice and succinct. Thanks Yemon and Willie.
Jul 8, 2010 at 19:37 comment added Willie Wong Aren't these just $C^{0,1}(D)$ and $C^{1,1}(D)$? Or am I missing something?
Jul 8, 2010 at 19:37 comment added Yemon Choi Your first space would, I think, usually be denoted by $Lip_1(D)$ or even just $Lip(D)$. There are several papers on "Lipschitz algebras" if you look on MathSciNet.
Jul 8, 2010 at 19:31 history asked Tom LaGatta CC BY-SA 2.5