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Sep 20, 2018 at 14:45 comment added KP Hart no separation axioms needed; that algebra is always complete: $\sup\mathcal{O}=\operatorname{int}\operatorname{cl}(\bigcup\mathcal{O})$.
Sep 20, 2018 at 12:37 history answered Tomasz Kania CC BY-SA 4.0