Timeline for A parametrization of stable matrices
Current License: CC BY-SA 4.0
21 events
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Sep 27, 2018 at 5:56 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 27, 2018 at 3:58 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 26, 2018 at 5:14 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 24, 2018 at 15:42 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 23, 2018 at 18:09 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 23, 2018 at 16:42 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 23, 2018 at 16:27 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 23, 2018 at 5:59 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 23, 2018 at 1:40 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 22, 2018 at 22:21 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 22, 2018 at 20:12 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 22, 2018 at 4:26 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 21, 2018 at 15:40 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 21, 2018 at 0:16 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 20, 2018 at 19:58 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 20, 2018 at 19:52 | history | edited | Ludwig | CC BY-SA 4.0 |
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Sep 20, 2018 at 13:45 | comment | added | Ludwig | @DirkLiebhold: All the eigenvalues of $A$ ($n$ eigenvalues) are real and strictly negative. | |
Sep 20, 2018 at 9:21 | comment | added | Dirk | Some info on the number of (real) eigenvalues of $A$? Would you also allow $A$ to have no real eigenvalues at all, as technically they would then also all be strictly negative? | |
Sep 20, 2018 at 5:58 | comment | added | Ludwig | @FedericoPoloni: no, $r$ is a parameter. | |
Sep 20, 2018 at 5:56 | comment | added | Federico Poloni | Is $r$ fixed? <character limit> | |
Sep 20, 2018 at 5:44 | history | asked | Ludwig | CC BY-SA 4.0 |