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Sep 17, 2018 at 3:11 comment added reuns $\zeta(s) \in ( 2^{-s}+\frac{3^{1-s}}{s-1}, 2^{-s}+3^{-s}+\frac{3^{1-s}}{s-1})$
Sep 16, 2018 at 21:20 answer added Craig Franze timeline score: 0
Sep 16, 2018 at 20:55 comment added Craig Franze I assume that the Euler-Maclaurin summation formula would do the trick. I would consult Montgomery & Vaughan's Multiplicative Number Theory, Appendix B, for details.
Sep 16, 2018 at 17:24 history asked tobias CC BY-SA 4.0