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Sep 16, 2018 at 5:50 vote accept jacob
Sep 15, 2018 at 1:15 answer added darx timeline score: 5
Sep 14, 2018 at 15:25 comment added Mohan @R.vanDobbendeBruyn You are right, it is a mistake.
Sep 14, 2018 at 14:21 comment added R. van Dobben de Bruyn @Mohan: your criterion is not true for non-proper varieties. For example, consider $\mathscr L = \mathcal O_X$ on $X = \mathbb A^2 \setminus \{0\}$, which is ample by Tag 01QE (and take $\mathscr F = \mathcal O_X$ as well).
Sep 14, 2018 at 13:24 comment added Mohan The best proof (not necessarily the easiest) would be to show that with your definition, a line bundle $L$ is ample if and only for any coherent sheaf $F$, $H^i(F\otimes L^n)=0$ for all large $n$ and all $i>0$. This property transfers nicely under finite maps.
Sep 14, 2018 at 13:21 history edited jacob CC BY-SA 4.0
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Sep 14, 2018 at 13:20 comment added jacob Could you please explain why?
Sep 14, 2018 at 13:19 comment added Mohan With your definition, a line bundle is ample if and only if it is when you pull it back under a finite map.
Sep 14, 2018 at 13:03 history asked jacob CC BY-SA 4.0