Timeline for Given any sequence of interpolating nodes, can we find a continuous function $f$ whose interpolating polynomials doesn't converge to $f$ point-wise
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 19, 2019 at 19:25 | answer | added | Lin Xuelei | timeline score: 0 | |
| S Sep 23, 2018 at 22:55 | history | bounty ended | user521337 | ||
| S Sep 23, 2018 at 22:55 | history | notice removed | user521337 | ||
| Sep 18, 2018 at 21:42 | vote | accept | user521337 | ||
| Sep 18, 2018 at 12:55 | answer | added | user111 | timeline score: 7 | |
| Sep 18, 2018 at 9:07 | comment | added | Wlod AA | Indeed, often I need something like $\ \forall\,\exists(A\Rightarrow\forall\ldots)$ | |
| S Sep 18, 2018 at 2:26 | history | bounty started | user521337 | ||
| S Sep 18, 2018 at 2:26 | history | notice added | user521337 | Draw attention | |
| Sep 16, 2018 at 5:32 | vote | accept | user521337 | ||
| Sep 16, 2018 at 5:32 | |||||
| Sep 14, 2018 at 0:57 | comment | added | Christian Remling | Your final expression could be scanned as "does not (converge at at least one point)" (= diverges everywhere) or as "(does not converge,) at at least one point." | |
| Sep 14, 2018 at 0:55 | history | edited | user521337 | CC BY-SA 4.0 |
added 2 characters in body
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| Sep 14, 2018 at 0:49 | history | asked | user521337 | CC BY-SA 4.0 |