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Sep 14, 2018 at 6:30 review Reopen votes
Sep 14, 2018 at 10:52
Sep 14, 2018 at 6:14 comment added David Roberts That typo was killing me. I had to fix it.
Sep 14, 2018 at 6:14 history edited David Roberts CC BY-SA 4.0
typo
Sep 13, 2018 at 18:15 comment added YCor @R.vanDobbendeBruyn Yes but this does not technically mean that the question (about trivial étale $\pi_1$) is not only about the underlying space.
Sep 13, 2018 at 17:39 comment added R. van Dobben de Bruyn @YCor: the topological space $\operatorname{Spec} \mathbb Z$ is contractible: you can contract everything to the generic point. But I suspected this was probably not the question...
Sep 13, 2018 at 16:23 comment added YCor It sounds awkward to phrase the question as a question about the "space" $Spec(Z)$. This seems to be a question about the scheme, not just the underlying topological space, isn't it?
Sep 13, 2018 at 13:27 history closed abx
R. van Dobben de Bruyn
Dan Petersen
Wojowu
S. Carnahan
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Sep 13, 2018 at 9:26 comment added user19475 See also mathoverflow.net/questions/26491/…
Sep 13, 2018 at 9:23 answer added nGroupoid timeline score: 10
Sep 12, 2018 at 6:03 comment added Konstantin Thanks a lot! Simply connected means trivial etale covers only.
Sep 12, 2018 at 4:50 review Close votes
Sep 13, 2018 at 13:30
Sep 12, 2018 at 4:32 comment added Felipe Voloch By a theorem of Minkowski, there are no unramified extensions of $\mathbb{Q}$.
Sep 12, 2018 at 4:31 comment added Kevin Casto If you're asking if it has trivial étale fundamental group, this just follows from the fact that $\mathbb Q$ has no unramified extensions.
Sep 12, 2018 at 4:16 comment added Will Chen What do you mean by simply connected?
Sep 12, 2018 at 4:15 review First posts
Sep 12, 2018 at 6:36
Sep 12, 2018 at 4:12 history asked Konstantin CC BY-SA 4.0