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Sep 11, 2018 at 18:54 history edited Qfwfq CC BY-SA 4.0
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Sep 11, 2018 at 15:36 history edited Liviu Nicolaescu CC BY-SA 4.0
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Sep 11, 2018 at 13:37 comment added Adam Ok, I think I get it. The only implicit fact is that $A(R,S)$ (and its derivatives) are in $V_n$. PS: $X_{u_i}\to Y_{u_i}$
Sep 11, 2018 at 13:14 history edited Liviu Nicolaescu CC BY-SA 4.0
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Sep 11, 2018 at 13:06 comment added Liviu Nicolaescu I've fixed the typos and I've simplified the proof.
Sep 11, 2018 at 13:05 history edited Liviu Nicolaescu CC BY-SA 4.0
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Sep 11, 2018 at 12:42 comment added Adam Thanks, I'm going through the proof, might have some questions. I think there are two typos : line 6 : $M^{i,j}\to M^{i,j,k}$ and line 10: $T_R\to A_R$
Sep 11, 2018 at 12:07 history answered Liviu Nicolaescu CC BY-SA 4.0