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Sep 11, 2018 at 1:01 vote accept Tomas
Sep 10, 2018 at 17:12 answer added Terry Tao timeline score: 7
Sep 10, 2018 at 16:01 comment added Christian Remling You are perhaps referring to the restriction problem: terrytao.wordpress.com/tag/restriction-conjecture But failure of restriction means that the restriction operator, initially defined on Schwartz functions, say, is unbounded, and not what you're asking for.
Sep 10, 2018 at 15:55 comment added Christian Remling Can you please clarify what you mean by $\widehat{f}=\infty$ on $S^{n-1}$?
Sep 10, 2018 at 14:46 history edited Willie Wong
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Sep 10, 2018 at 8:46 history asked Tomas CC BY-SA 4.0