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Oct 3, 2018 at 20:12 history closed Wlodek Kuperberg
Ben McKay
arsmath
Pace Nielsen
Ilya Bogdanov
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Sep 7, 2018 at 21:04 comment added Robert Israel Actually I think you want it totally ordered. In a partially ordered set, there are two possible meanings of argmin (you may require $f(x)$ to be a minimal element of $f(X)$ or a least element of $f(X)$), and neither of those is preserved by (strictly) monotone increasing functions $g$. The problem is that you could have $g(f(a)) < g(f(b))$ where $f(a)$ and $f(b)$ are incomparable.
Sep 7, 2018 at 16:16 history edited ABIM CC BY-SA 4.0
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Sep 7, 2018 at 15:39 comment added Pushpendre Monotonicity is not sufficient, If $g$ is monotone decreasing then the minima is not preserved. Consider $X = [0, 1], f(x) = x, g(x) = 1-x$
Sep 7, 2018 at 15:32 comment added Robert Israel I think you mean $f: X \to Y$ and $g: Y \to Z$, where $Y$ and $Z$ are partially ordered sets: otherwise $\text{argmin}$ has no meaning.
Sep 7, 2018 at 15:05 review Close votes
Oct 3, 2018 at 20:12
Sep 7, 2018 at 13:29 history asked ABIM CC BY-SA 4.0