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Jul 8, 2010 at 19:05 answer added Pace Nielsen timeline score: 1
Jul 8, 2010 at 17:56 vote accept Shizhuo Zhang
Jul 8, 2010 at 14:55 answer added BCnrd timeline score: 7
Jul 8, 2010 at 12:20 answer added Georges Elencwajg timeline score: 3
Jul 8, 2010 at 6:54 comment added Robin Chapman The proof you gave is perefctly natural: it observed that the fibres of the two affine schemes at the closed point of characteristic $p$ are not isomorphic. :-)
Jul 8, 2010 at 6:44 comment added Robin Chapman Why not ask whether the "same" rings with $\mathbb{Z}$ replaced by $\mathbb{Q}$ (or your favourite characteristic zero field) are isomorphic?
Jul 8, 2010 at 6:42 history edited Shizhuo Zhang CC BY-SA 2.5
added 144 characters in body
Jul 8, 2010 at 6:31 history asked Shizhuo Zhang CC BY-SA 2.5