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Sep 4, 2018 at 14:58 vote accept wonderich
Sep 4, 2018 at 3:21 comment added Arun Debray @annieheart the Poincaré dual to $0\in H^k(\mathbb{RP}^n; \mathbb Z/2)$ is an $(n-k)$-dimensional homology class, so a submanifold representing it is an $(n-k)$-dimensional manifold. That's what I meant by "the correct dimension." Since this homology class is zero, it's represented by an $(n-k)$-cycle which is the boundary of some $(n-k+1)$-cycle. For example, you could take an $(n-k)$-dimensional submanifold $N\subset\mathbb{RP}^n$ such that there's an $(n-k+1)$-dimensional submanifold $W\subset\mathbb{RP}^n$ with $N = \partial W$, and one says $N$ bounds.
Sep 4, 2018 at 2:50 vote accept wonderich
Sep 4, 2018 at 3:13
Sep 4, 2018 at 2:49 comment added annie marie cœur What is the meaning of "a submanifold of the correct dimension which bounds"??? Thanks...
Sep 3, 2018 at 21:40 history answered Arun Debray CC BY-SA 4.0