Timeline for How can one smoothly close a non closed curve?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Sep 4, 2018 at 0:35 | vote | accept | Matheus Andrade | ||
| Sep 4, 2018 at 0:06 | answer | added | Joseph O'Rourke | timeline score: 6 | |
| Sep 3, 2018 at 22:38 | comment | added | Matheus Andrade | I hadn't realized that, thanks. I don't want $\alpha \cup \beta$ to be necessarily simple, just smoothness will work well enough. | |
| Sep 3, 2018 at 22:37 | history | edited | Matheus Andrade | CC BY-SA 4.0 |
added 14 characters in body
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| Sep 3, 2018 at 22:35 | comment | added | Joseph O'Rourke | It appears from your drawing that $\alpha'(0) = -\alpha'(L)$: The tangents are oppositely oriented. Also, do you require that $\alpha + \beta$ be simple, i.e., non-self-intersecting? | |
| Sep 3, 2018 at 22:24 | history | edited | Matheus Andrade | CC BY-SA 4.0 |
added 99 characters in body
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| Sep 3, 2018 at 22:23 | comment | added | Matheus Andrade | I thought that was implied, but clearly it's not. I'll correct my post. | |
| Sep 3, 2018 at 22:16 | comment | added | Lee Mosher | Are you asking how to prove existence of $\beta$? Or what are you asking? | |
| Sep 3, 2018 at 21:35 | history | asked | Matheus Andrade | CC BY-SA 4.0 |