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May 3 at 13:44 history edited LSpice CC BY-SA 4.0
Displaying displayed equations, while this is on the front page
May 25, 2020 at 1:18 comment added Joe Silverman @AbdelmalekAbdesselam It's certainly true that there is no universally used choice. However, up to translation by an integer, there is a canonical choice if one wants a formula that has the correct properties in all characteristics, including characteristic 2 and 3. So that would seem to make the "number theorists'" version canonical, up to (as I said) translation by an integer. OTOH, if you're doing complex analysis, one could take the "$j$-invariant" of $X^3+AX+B$ to be $$\frac{(\pi^e+i\tan(\pi//\sqrt2))\cdot4A^3}{4A^3+27B^2},$$ for example. :)
May 24, 2020 at 23:15 history edited Abdelmalek Abdesselam CC BY-SA 4.0
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May 24, 2020 at 23:01 comment added Abdelmalek Abdesselam There are different conventions for what the proper normalization of $j$ is. Number theorists have their preferred choice. Folks working on moonshine matters have their own. Classical invariant theorists also. The is no universally canonical choice.
May 24, 2020 at 22:15 comment added Oliver Please beware you are calculating J which is j/1728
Jul 8, 2010 at 13:55 vote accept David Marín
Jul 7, 2010 at 22:32 history answered Abdelmalek Abdesselam CC BY-SA 2.5