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Sep 1, 2018 at 7:38 history edited bof CC BY-SA 4.0
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Aug 31, 2018 at 22:05 history edited bof CC BY-SA 4.0
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Aug 31, 2018 at 21:59 comment added bof @GerhardPaseman Yes, of course. If $G=(V,E)$ is a self-complementary graph, let $\alpha\in\operatorname{Sym}(V)$ be an anti-automorphism of $G.$
Aug 31, 2018 at 21:40 comment added Gerhard Paseman Do all such finite complementary graphs arise this way? Gerhard "Not Fishing For More Complements" Paseman, 2018.08.31.
Aug 31, 2018 at 21:20 history answered bof CC BY-SA 4.0