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Aug 25, 2018 at 10:05 answer added Andrej Bauer timeline score: 9
Aug 24, 2018 at 22:29 comment added Michal R. Przybylek @MattF. your comment is not correct. An injection form P(N) to N is not consistent with IZF. The statement that there can be no injection from P(A) to A for any A follows from Cantor's argument, which is purely constructive. Perhaps, you have confused P(N) with $N^N$, or $2^N$...
Aug 24, 2018 at 20:30 comment added Zuhair Al-Johar @MattF.can you please add this as an answer, and if you know of other versions, then please mention them.
Aug 24, 2018 at 20:16 comment added user44143 IZF (intutionistic Zermelo-Frankel) is a strong theory, and consistent with an injection from P(N) to N. Such an injection follows from the version of Church’s thesis that “all functions are recursive”.
Aug 24, 2018 at 3:50 history edited user44143 CC BY-SA 4.0
reformatted and emphasized questions
Aug 23, 2018 at 23:25 comment added Zuhair Al-Johar @DavidRoberts thanks
Aug 23, 2018 at 22:29 comment added David Roberts You really should use the lo.logic tag, this is the second time I've added it to a question you asked in this area. Also, use \text as a wrapper for when you want text inside a math environment
Aug 23, 2018 at 22:28 history edited David Roberts CC BY-SA 4.0
Added lo.logic tag, cleaned up TeX
Aug 23, 2018 at 21:26 comment added Zuhair Al-Johar @GerhardPaseman if for example Con(NF) is proved then we can have a fragment that can interpret $\omega$_order arithmetic and yet be consistent with this notion. To me any fragment near the strength of $PA$ is not to be considered weak.
Aug 23, 2018 at 19:52 comment added Gerhard Paseman It will have to be weak to keep from forming the set of members y of x which do not belong to f(y), while still having the power to express your notion. Gerhard "Not Sure Of The Utility" Paseman, 2018.08.23.
Aug 23, 2018 at 19:26 history asked Zuhair Al-Johar CC BY-SA 4.0