Skip to main content
4 events
when toggle format what by license comment
Aug 21, 2018 at 22:30 comment added Ramiro de la Vega @TarasBanakh, Also under $\mathfrak{b}=\aleph_1$ and under $\mathfrak{d}=\mathfrak{c}$.
Aug 21, 2018 at 20:44 comment added Taras Banakh It seems that the paracompactness of the box topology on $\mathbb R^\omega$ can be proved under $\mathfrak b=\mathfrak d$ (which is equivalent to the existence of a scale in $\omega^\omega$).
Aug 21, 2018 at 16:29 comment added James E Hanson Wikipedia says that the box topology on $\mathbb{R}^\omega$ is paracompact if the continuum hypothesis holds and paracompact spaces are metacompact. So under CH the answer is positive.
Aug 21, 2018 at 14:03 history asked Dominic van der Zypen CC BY-SA 4.0