Skip to main content
Notice removed Draw attention by CommunityBot
Bounty Ended with no winning answer by CommunityBot
Notice added Draw attention by Ali Taghavi
Bounty Started worth 100 reputation by Ali Taghavi
Notice removed Draw attention by CommunityBot
Bounty Ended with no winning answer by CommunityBot
Notice added Draw attention by Ali Taghavi
Bounty Started worth 50 reputation by Ali Taghavi
added 184 characters in body
Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The operator $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since it leads to a gradient vector field, but a gradient vector field has no any closed orbit.

As another question: Is there a name or terminology for the following compatibility of symplectic structure and Riemannian structure?

$$d^*\omega \wedge dd^* \omega=0$$

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The operator $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since it leads to a gradient vector field, but a gradient vector field has no any closed orbit.

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The operator $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since it leads to a gradient vector field, but a gradient vector field has no any closed orbit.

As another question: Is there a name or terminology for the following compatibility of symplectic structure and Riemannian structure?

$$d^*\omega \wedge dd^* \omega=0$$

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The opertoroperator $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since we leadsince it leads to a gradient vector field, but a gradient vector field has no any closed orbit.

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The opertor $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since we lead to a gradient vector field, but a gradient vector field has no any closed orbit.

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The operator $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since it leads to a gradient vector field, but a gradient vector field has no any closed orbit.

added 23 characters in body
Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The opertor $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since we lead to a gradient vector field which, but a gradient vector field has no any closed orbit.

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The opertor $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since we lead to a gradient vector field which has no any closed orbit.

Is there a symplectic manifold $(M,\omega)$ equipped with a Riemannian metric such that $d^* \omega \wedge dd^*\omega=0$ and there is a compact leaf for the foliation of $M\setminus S$ defined by $d^* \omega =0$ where $S$ is the singular points of $d^* \omega$?(The opertor $d^*$ is the adjoint of the exterior derivative $d$).

In dimension $2$ the answer is negative since we lead to a gradient vector field, but a gradient vector field has no any closed orbit.

added 66 characters in body
Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123
Loading
Source Link
Ali Taghavi
  • 356
  • 8
  • 31
  • 123
Loading