Timeline for What does it mean to say the first Goodwillie derivative of $TC$ is $THH$?
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 21, 2018 at 17:20 | vote | accept | Tim Campion | ||
| Aug 21, 2018 at 2:09 | answer | added | Tom Goodwillie | timeline score: 13 | |
| Aug 20, 2018 at 22:03 | answer | added | Nicholas Kuhn | timeline score: 8 | |
| Aug 17, 2018 at 7:46 | comment | added | Karol Szumiło | I don't know if this helps with your $TC$ question, but this paper arxiv.org/abs/math/0601221 sets up some foundations of Goodwillie calculus for non-finitary functors. | |
| Aug 16, 2018 at 15:30 | comment | added | Denis Nardin | I will write a proper answer later, but you are supposed to be taking the derivative in the coefficients, that is the theorem is simply saying that $THH(A;M)=\mathrm{colim}_n\Omega^n TC(A;\Sigma^nM)$ for all ring spectra $A$ and $A$-modules $M$. | |
| Aug 16, 2018 at 14:15 | history | asked | Tim Campion | CC BY-SA 4.0 |