Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
By parallelogram rule in "Murray-von Numann equivalency" we have $p-p\wedge(1-e)\sim e-e\wedge(1-p)$. Hence, $p-p\wedge(1-e)$ is always finite, if $e$ is finite.
By parallelogram rule in "Murray-von Numann equivalency" we have $p-p\wedge(1-e)\sim e-e\wedge(1-p)$. Hence, $p-p\wedge(1-e)$ is always finite, if $e$ is.
By parallelogram rule in "Murray-von Numann equivalency" we have $p-p\wedge(1-e)\sim e-e\wedge(1-p)$. Hence, $p-p\wedge(1-e)$ is always finite, if $e$ is finite.
By parallelogram rule in "Murray-von Numann equivalency" we have $p-p\wedge(1-e)\sim e-e\wedge(1-p)$. Hence, $p-p\wedge(1-e)$ is always finite, if $e$ is.
