Timeline for An inequality with rotation
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Sep 6, 2018 at 4:29 | comment | added | Willie Wong | Let $Q(z) = 2 + z$. Consider $P(z) = \lambda Q(z)$ for $\lambda \in \mathbb{R}$. Let $\alpha = 1$. Evaluating the left hand side on $z = 1$ gives $| 2\lambda - 6 \lambda /(2\lambda + 1)|$. The right hand side is exactly $6\lambda / (2\lambda + 1)$. As $\lambda \nearrow +\infty$ you see that your inequality is false. You probably want $n \geq 2$ at least. | |
| Sep 6, 2018 at 1:32 | history | edited | Venkat | CC BY-SA 4.0 |
It has to be a non-constant polynomial by default and hence explicitly expressed as $n\geq 1.$
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| Sep 4, 2018 at 12:33 | comment | added | Philipp Lampe | This is wrong. The RHS is negative for $P(z)=2$. | |
| Aug 13, 2018 at 16:36 | history | asked | Venkat | CC BY-SA 4.0 |