Skip to main content

Timeline for Finite maps and jacobian condition

Current License: CC BY-SA 4.0

2 events
when toggle format what by license comment
Aug 13, 2018 at 16:15 comment added R. van Dobben de Bruyn I used $\det J_f = 1 \in A$ instead of $\det J_f = 1 \in R[X_1,\ldots,X_n]$ because the latter is extremely rare. For $R = \mathbb C$, the Jacobian conjecture says that $\det J_f = 1 \in \mathbb C[X_1,\ldots,X_n]$ implies that $f \colon \mathbb A^n_{\mathbb C} \to \mathbb A^n_{\mathbb C}$ is an isomorphism. In particular, $A \cong \mathbb C$, which is not a very interesting case.
Aug 13, 2018 at 16:01 history answered R. van Dobben de Bruyn CC BY-SA 4.0