Timeline for Convex hull of piece-wise linear functions
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
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| S Aug 13, 2018 at 19:19 | history | suggested | Rodrigo de Azevedo |
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| Aug 13, 2018 at 19:07 | comment | added | Dirk | @PietroMajer Doh, you're right, of course. | |
| Aug 13, 2018 at 19:05 | comment | added | Pietro Majer | @Dirk taking the convex hull produces piece-wise affine functions, each with finitely many pieces, though with possibly any number of pieces. | |
| Aug 13, 2018 at 18:33 | review | Suggested edits | |||
| S Aug 13, 2018 at 19:19 | |||||
| Aug 13, 2018 at 17:51 | comment | added | Dirk | Err, that's quite a different problem now... Anyway, I still think that the convex hull makes the $K$ superfluous. | |
| Aug 13, 2018 at 17:49 | comment | added | O. Richard | @Dirk I modified the problem statement a bit. Thanks for clarifying | |
| Aug 13, 2018 at 17:48 | history | edited | O. Richard | CC BY-SA 4.0 |
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| Aug 13, 2018 at 17:42 | comment | added | Dirk | But taking the convex hull should allow at least countably many kinks. Or are these $a_k$'s and $b_k$'s fixed? | |
| Aug 13, 2018 at 17:40 | review | Close votes | |||
| Aug 19, 2018 at 12:09 | |||||
| Aug 13, 2018 at 17:33 | comment | added | O. Richard | @Dirk Is it obvious? Here the number of pieces is fixed. | |
| Aug 13, 2018 at 17:32 | comment | added | O. Richard | @PietroMajer Why is $\mathcal{F}$ convex? The number of pieces is fixed as $K$. | |
| Aug 13, 2018 at 17:31 | history | edited | O. Richard | CC BY-SA 4.0 |
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| Aug 13, 2018 at 16:57 | comment | added | Dirk | Isn't the convex hull of $\mathcal{F}$ the set of all convex functions? | |
| Aug 13, 2018 at 16:28 | comment | added | Pietro Majer | Since $\mathcal{F}$ is a convex cone, the convex hull is the same set as $\mathcal{F}-\mathcal{F}$ | |
| Aug 13, 2018 at 15:17 | history | asked | O. Richard | CC BY-SA 4.0 |