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Aug 13, 2018 at 14:36 vote accept Ben Grossmann
Aug 13, 2018 at 14:24 history edited Ben Grossmann CC BY-SA 4.0
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Aug 13, 2018 at 14:23 comment added Ben Grossmann @TomGoodwillie well spotted... either seems to be enough, but for now let's suppose that $\phi$ is bijective.
Aug 13, 2018 at 13:57 answer added Zach Teitler timeline score: 1
Aug 13, 2018 at 13:39 answer added Tom Goodwillie timeline score: 2
Aug 13, 2018 at 13:18 comment added Tom Goodwillie Do you mean to assume that $\phi$ is injective? Bijective? Any constant map $\Phi:X\to X$ satisfies the condition as written.
Aug 13, 2018 at 11:54 history edited Ben Grossmann CC BY-SA 4.0
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Aug 13, 2018 at 7:12 answer added Laurent Moret-Bailly timeline score: 4
Aug 12, 2018 at 21:10 history edited Ben Grossmann CC BY-SA 4.0
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Aug 12, 2018 at 21:10 review First posts
Aug 12, 2018 at 21:49
Aug 12, 2018 at 21:04 history asked Ben Grossmann CC BY-SA 4.0