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Aug 9, 2018 at 20:42 vote accept T. Amdeberhan
Aug 8, 2018 at 21:13 comment added darij grinberg This might be in arxiv.org/abs/1508.01987v1 : your sequence $a_n$ fits into both classes; in particular it is $\mathbf{a}\left(X, 1, 1\right)$. So I'd look at Theorem 5 in particular.
Aug 8, 2018 at 21:08 history edited T. Amdeberhan CC BY-SA 4.0
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Aug 8, 2018 at 21:02 answer added darij grinberg timeline score: 24
Aug 8, 2018 at 21:00 comment added Marty Well, $\nu_2(n+13) = \nu_2((n+1) + 12)$. And 12 is special :)
Aug 8, 2018 at 20:39 history asked T. Amdeberhan CC BY-SA 4.0