Timeline for Calculate percentage of symmetry of a given matrix
Current License: CC BY-SA 4.0
10 events
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| Aug 7, 2018 at 15:28 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Aug 7, 2018 at 14:35 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Aug 7, 2018 at 14:25 | comment | added | Geoff Robinson | @LSpice : Because I was using the OP's terminology rather than my own. | |
| Aug 7, 2018 at 13:43 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Aug 7, 2018 at 13:33 | comment | added | LSpice | @GeoffRobinson, why the 'sic' on '"percentage"'? | |
| Aug 7, 2018 at 13:18 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Aug 7, 2018 at 13:17 | comment | added | lydiaP | That is also what I was wondering, that if I have higher values in a Matrix A than in a Matrix B but the "symmetry" is the same, then A will have a higher degree of asymmetry even it should be the same value, right? So dividing maybe the range by the largest value of the matrix? | |
| Aug 7, 2018 at 13:17 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Aug 7, 2018 at 13:07 | comment | added | Geoff Robinson | Wouldn't you want some sort of normalization to answer the question? By that I mean that, given a matrix $A$ ( I guess some $n \times n$ real matrix is intended), the "percentage" (sic) of how symmetric $A$ is should remain unchanged if we replace $A$ by a non-zero scalar multiple. | |
| Aug 7, 2018 at 12:39 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |