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Jun 16, 2020 at 10:04 comment added Jianrong Li @Johannes Trost, thank you very much for your help last time. If $v_1, v_2$ have large overlap, how do you compute asymptotic of ${|v_1| - O(\min(|v_1|, |v_2|)^v) \choose x_1 - d}$. Is it possible to show that $f(v_1, v_2)<1$ when $|v_1|, |v_2|$ are large and $v_1, v_2$ have large overlap?
Aug 5, 2018 at 19:02 history edited Jianrong Li CC BY-SA 4.0
added 36 characters in body
Aug 5, 2018 at 18:44 history edited Jianrong Li CC BY-SA 4.0
added 2 characters in body
Aug 5, 2018 at 15:36 comment added Jianrong Li @Johannes Trost, thank you very much. I only need to show that $f(v_1,v_2)$ is strictly smaller than 1 when $|v_1|, |v_2|$ are large enough.
Aug 5, 2018 at 14:35 history edited Jianrong Li CC BY-SA 4.0
deleted 30 characters in body
S Aug 5, 2018 at 14:31 history suggested Johannes Trost CC BY-SA 4.0
Added missing set-of-natural-numbers and some absolute brackets
Aug 5, 2018 at 14:30 review Suggested edits
S Aug 5, 2018 at 14:31
Aug 5, 2018 at 14:20 comment added Johannes Trost The asymptotics will be very different depending on the size of $|v_{1} v_{2}|$. If the vectors have a small overlap, $|v_{1} v_{2}|\ll \min(v_{1}, v_{2})$, then one might neglect $|v_{1} v_{2}|$. If the vectors have large overlap, then $|v_{1} v_{2}| = O(\min(v_{1}, v_{2}))$ and should not be neglected. Or let it be $|v_{1} v_{2}|= O(\min(v_{1}, v_{2})^\nu)$ with some real exponent $\nu$, presumably smaller than one. And these are only some examples. The results could be very different in all these cases. Before I start working, it would be helpful, if many possibilities could be excluded.
Aug 5, 2018 at 14:16 history edited Brendan McKay CC BY-SA 4.0
make abs value brackets bigger
Aug 5, 2018 at 13:40 comment added Jianrong Li @JohannesTrost, I am looking for something like ${2n \choose n} \sim \frac{4^{n}}{\sqrt{n \pi}}$ ($n \to \infty$).
Aug 5, 2018 at 13:30 comment added Johannes Trost So you are not looking for an asymptotic expansion, but rather an efficient (approximate) algorithm for large $|v_{1}|$, $|v_{2}|$ ?
Aug 5, 2018 at 13:06 comment added Jianrong Li @Johannes Trost, thank you very much. The vectors $v_1, v_2$ are given. So $v_1 v_2$ is known and $|v_1 v_2|$ is known.
Aug 5, 2018 at 12:42 comment added Johannes Trost Have you any further information on the behaviour of $|v_{1} v_{2}|$ ? As it stands it could be anything in $\left [ 0, \min(|v_{1}|,|v_{2}|) \right]$. Maybe $|v_{1} v_{2}|= O(\min(|v_{1}|, |v_{2}|) )$ ?
Aug 5, 2018 at 12:23 history asked Jianrong Li CC BY-SA 4.0