Timeline for How to choose compactly supported smooth $h$ so $h^2(x)+ h^2(x-1)=1$ for all $x\in [0,1],$ and $\int_{-3/4}^{3/4} |h(x)|^2 dx =3/2$?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 5, 2018 at 14:09 | comment | added | Math Learner | Can we say anything for the $[-3/4, 3/4 ]$ supported function. | |
| Aug 5, 2018 at 14:08 | comment | added | Math Learner | Oh, Thanks. It was typo. I have edited the question. | |
| Aug 5, 2018 at 2:38 | comment | added | Iosif Pinelis | In your question, it was assumed that the support of $h$ is $[-1/3,1/3]$, and this is what is assumed in my answer as well. | |
| Aug 5, 2018 at 2:27 | comment | added | Math Learner | Thanks. But we need to start with support of $h$ is $[-3/4, 3/4].$ Can we say anything for this. PS: If support of $h$ is $[-1/3, 1/3]$ then $h^2(x)+h^{2}(x-1)=1$ for all $x\in [0,1]$ is NOT possible. | |
| Aug 5, 2018 at 2:12 | history | answered | Iosif Pinelis | CC BY-SA 4.0 |