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Aug 6, 2018 at 14:12 vote accept JKreft
Aug 3, 2018 at 9:01 history edited JKreft CC BY-SA 4.0
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Aug 3, 2018 at 9:00 answer added JKreft timeline score: 1
Aug 3, 2018 at 8:41 comment added JKreft YES! I'd never heard of them before. I have the necessary condition (in a different form) that n=j^2+j+1. Ah, I see that it's not a prime power (since k=7, j= 6), which all my other j's are.
Aug 3, 2018 at 7:40 comment added Seva Are perfect difference sets what you are after?
Aug 3, 2018 at 5:48 comment added JKreft The $a_i$ allow a "tiling" of the space by incrementing $\bmod n$. That is, if I take the $n$ additive translations of the list of $a_i$, I get $n$ $k-$element lists where each pair of translations has exactly one element in common.
Aug 3, 2018 at 5:44 history asked JKreft CC BY-SA 4.0